Optimal. Leaf size=217 \[ -\frac{2 \text{PolyLog}\left (3,1-\frac{2}{1+i a x}\right )}{a^5 c}-\frac{4 i \tan ^{-1}(a x) \text{PolyLog}\left (2,1-\frac{2}{1+i a x}\right )}{a^5 c}-\frac{\log \left (a^2 x^2+1\right )}{2 a^5 c}+\frac{x^3 \tan ^{-1}(a x)^3}{3 a^2 c}-\frac{x^2 \tan ^{-1}(a x)^2}{2 a^3 c}+\frac{\tan ^{-1}(a x)^4}{4 a^5 c}-\frac{x \tan ^{-1}(a x)^3}{a^4 c}-\frac{4 i \tan ^{-1}(a x)^3}{3 a^5 c}-\frac{\tan ^{-1}(a x)^2}{2 a^5 c}+\frac{x \tan ^{-1}(a x)}{a^4 c}-\frac{4 \log \left (\frac{2}{1+i a x}\right ) \tan ^{-1}(a x)^2}{a^5 c} \]
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Rubi [A] time = 0.626298, antiderivative size = 217, normalized size of antiderivative = 1., number of steps used = 19, number of rules used = 9, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.409, Rules used = {4916, 4852, 4846, 260, 4884, 4920, 4854, 4994, 6610} \[ -\frac{2 \text{PolyLog}\left (3,1-\frac{2}{1+i a x}\right )}{a^5 c}-\frac{4 i \tan ^{-1}(a x) \text{PolyLog}\left (2,1-\frac{2}{1+i a x}\right )}{a^5 c}-\frac{\log \left (a^2 x^2+1\right )}{2 a^5 c}+\frac{x^3 \tan ^{-1}(a x)^3}{3 a^2 c}-\frac{x^2 \tan ^{-1}(a x)^2}{2 a^3 c}+\frac{\tan ^{-1}(a x)^4}{4 a^5 c}-\frac{x \tan ^{-1}(a x)^3}{a^4 c}-\frac{4 i \tan ^{-1}(a x)^3}{3 a^5 c}-\frac{\tan ^{-1}(a x)^2}{2 a^5 c}+\frac{x \tan ^{-1}(a x)}{a^4 c}-\frac{4 \log \left (\frac{2}{1+i a x}\right ) \tan ^{-1}(a x)^2}{a^5 c} \]
Antiderivative was successfully verified.
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Rule 4916
Rule 4852
Rule 4846
Rule 260
Rule 4884
Rule 4920
Rule 4854
Rule 4994
Rule 6610
Rubi steps
\begin{align*} \int \frac{x^4 \tan ^{-1}(a x)^3}{c+a^2 c x^2} \, dx &=-\frac{\int \frac{x^2 \tan ^{-1}(a x)^3}{c+a^2 c x^2} \, dx}{a^2}+\frac{\int x^2 \tan ^{-1}(a x)^3 \, dx}{a^2 c}\\ &=\frac{x^3 \tan ^{-1}(a x)^3}{3 a^2 c}+\frac{\int \frac{\tan ^{-1}(a x)^3}{c+a^2 c x^2} \, dx}{a^4}-\frac{\int \tan ^{-1}(a x)^3 \, dx}{a^4 c}-\frac{\int \frac{x^3 \tan ^{-1}(a x)^2}{1+a^2 x^2} \, dx}{a c}\\ &=-\frac{x \tan ^{-1}(a x)^3}{a^4 c}+\frac{x^3 \tan ^{-1}(a x)^3}{3 a^2 c}+\frac{\tan ^{-1}(a x)^4}{4 a^5 c}-\frac{\int x \tan ^{-1}(a x)^2 \, dx}{a^3 c}+\frac{\int \frac{x \tan ^{-1}(a x)^2}{1+a^2 x^2} \, dx}{a^3 c}+\frac{3 \int \frac{x \tan ^{-1}(a x)^2}{1+a^2 x^2} \, dx}{a^3 c}\\ &=-\frac{x^2 \tan ^{-1}(a x)^2}{2 a^3 c}-\frac{4 i \tan ^{-1}(a x)^3}{3 a^5 c}-\frac{x \tan ^{-1}(a x)^3}{a^4 c}+\frac{x^3 \tan ^{-1}(a x)^3}{3 a^2 c}+\frac{\tan ^{-1}(a x)^4}{4 a^5 c}-\frac{\int \frac{\tan ^{-1}(a x)^2}{i-a x} \, dx}{a^4 c}-\frac{3 \int \frac{\tan ^{-1}(a x)^2}{i-a x} \, dx}{a^4 c}+\frac{\int \frac{x^2 \tan ^{-1}(a x)}{1+a^2 x^2} \, dx}{a^2 c}\\ &=-\frac{x^2 \tan ^{-1}(a x)^2}{2 a^3 c}-\frac{4 i \tan ^{-1}(a x)^3}{3 a^5 c}-\frac{x \tan ^{-1}(a x)^3}{a^4 c}+\frac{x^3 \tan ^{-1}(a x)^3}{3 a^2 c}+\frac{\tan ^{-1}(a x)^4}{4 a^5 c}-\frac{4 \tan ^{-1}(a x)^2 \log \left (\frac{2}{1+i a x}\right )}{a^5 c}+\frac{\int \tan ^{-1}(a x) \, dx}{a^4 c}-\frac{\int \frac{\tan ^{-1}(a x)}{1+a^2 x^2} \, dx}{a^4 c}+\frac{2 \int \frac{\tan ^{-1}(a x) \log \left (\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx}{a^4 c}+\frac{6 \int \frac{\tan ^{-1}(a x) \log \left (\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx}{a^4 c}\\ &=\frac{x \tan ^{-1}(a x)}{a^4 c}-\frac{\tan ^{-1}(a x)^2}{2 a^5 c}-\frac{x^2 \tan ^{-1}(a x)^2}{2 a^3 c}-\frac{4 i \tan ^{-1}(a x)^3}{3 a^5 c}-\frac{x \tan ^{-1}(a x)^3}{a^4 c}+\frac{x^3 \tan ^{-1}(a x)^3}{3 a^2 c}+\frac{\tan ^{-1}(a x)^4}{4 a^5 c}-\frac{4 \tan ^{-1}(a x)^2 \log \left (\frac{2}{1+i a x}\right )}{a^5 c}-\frac{4 i \tan ^{-1}(a x) \text{Li}_2\left (1-\frac{2}{1+i a x}\right )}{a^5 c}+\frac{i \int \frac{\text{Li}_2\left (1-\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx}{a^4 c}+\frac{(3 i) \int \frac{\text{Li}_2\left (1-\frac{2}{1+i a x}\right )}{1+a^2 x^2} \, dx}{a^4 c}-\frac{\int \frac{x}{1+a^2 x^2} \, dx}{a^3 c}\\ &=\frac{x \tan ^{-1}(a x)}{a^4 c}-\frac{\tan ^{-1}(a x)^2}{2 a^5 c}-\frac{x^2 \tan ^{-1}(a x)^2}{2 a^3 c}-\frac{4 i \tan ^{-1}(a x)^3}{3 a^5 c}-\frac{x \tan ^{-1}(a x)^3}{a^4 c}+\frac{x^3 \tan ^{-1}(a x)^3}{3 a^2 c}+\frac{\tan ^{-1}(a x)^4}{4 a^5 c}-\frac{4 \tan ^{-1}(a x)^2 \log \left (\frac{2}{1+i a x}\right )}{a^5 c}-\frac{\log \left (1+a^2 x^2\right )}{2 a^5 c}-\frac{4 i \tan ^{-1}(a x) \text{Li}_2\left (1-\frac{2}{1+i a x}\right )}{a^5 c}-\frac{2 \text{Li}_3\left (1-\frac{2}{1+i a x}\right )}{a^5 c}\\ \end{align*}
Mathematica [A] time = 0.246642, size = 154, normalized size = 0.71 \[ \frac{48 i \tan ^{-1}(a x) \text{PolyLog}\left (2,-e^{2 i \tan ^{-1}(a x)}\right )-24 \text{PolyLog}\left (3,-e^{2 i \tan ^{-1}(a x)}\right )-6 \log \left (a^2 x^2+1\right )+4 a^3 x^3 \tan ^{-1}(a x)^3-6 a^2 x^2 \tan ^{-1}(a x)^2+3 \tan ^{-1}(a x)^4-12 a x \tan ^{-1}(a x)^3+16 i \tan ^{-1}(a x)^3-6 \tan ^{-1}(a x)^2+12 a x \tan ^{-1}(a x)-48 \tan ^{-1}(a x)^2 \log \left (1+e^{2 i \tan ^{-1}(a x)}\right )}{12 a^5 c} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 3.701, size = 1740, normalized size = 8. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{x^{4} \arctan \left (a x\right )^{3}}{a^{2} c x^{2} + c}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{x^{4} \operatorname{atan}^{3}{\left (a x \right )}}{a^{2} x^{2} + 1}\, dx}{c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{4} \arctan \left (a x\right )^{3}}{a^{2} c x^{2} + c}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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